Optimal. Leaf size=133 \[ \frac{31}{20 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} a^{5/2} d}-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{13}{30 a d (a+i a \tan (c+d x))^{3/2}} \]
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Rubi [A] time = 0.236378, antiderivative size = 133, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192, Rules used = {3558, 3590, 3526, 3480, 206} \[ \frac{31}{20 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} a^{5/2} d}-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{13}{30 a d (a+i a \tan (c+d x))^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3558
Rule 3590
Rule 3526
Rule 3480
Rule 206
Rubi steps
\begin{align*} \int \frac{\tan ^3(c+d x)}{(a+i a \tan (c+d x))^{5/2}} \, dx &=-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{\int \frac{\tan (c+d x) \left (-2 a+\frac{9}{2} i a \tan (c+d x)\right )}{(a+i a \tan (c+d x))^{3/2}} \, dx}{5 a^2}\\ &=-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{13}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{i \int \frac{-\frac{13 a^2}{2}+9 i a^2 \tan (c+d x)}{\sqrt{a+i a \tan (c+d x)}} \, dx}{10 a^4}\\ &=-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{13}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{31}{20 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{i \int \sqrt{a+i a \tan (c+d x)} \, dx}{8 a^3}\\ &=-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{13}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{31}{20 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,\sqrt{a+i a \tan (c+d x)}\right )}{4 a^2 d}\\ &=\frac{\tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} a^{5/2} d}-\frac{\tan ^2(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{13}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{31}{20 a^2 d \sqrt{a+i a \tan (c+d x)}}\\ \end{align*}
Mathematica [A] time = 1.12663, size = 135, normalized size = 1.02 \[ \frac{e^{-6 i (c+d x)} \left (1+e^{2 i (c+d x)}\right )^{3/2} \sec ^2(c+d x) \left (\sqrt{1+e^{2 i (c+d x)}} \left (-19 e^{2 i (c+d x)}+83 e^{4 i (c+d x)}+3\right )+15 e^{5 i (c+d x)} \sinh ^{-1}\left (e^{i (c+d x)}\right )\right )}{240 a^2 d \sqrt{a+i a \tan (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.022, size = 93, normalized size = 0.7 \begin{align*} -2\,{\frac{1}{{a}^{2}d} \left ( -1/16\,{\frac{\sqrt{2}}{\sqrt{a}}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{a+ia\tan \left ( dx+c \right ) }\sqrt{2}}{\sqrt{a}}} \right ) }-{\frac{7}{8\,\sqrt{a+ia\tan \left ( dx+c \right ) }}}+{\frac{5\,a}{12\, \left ( a+ia\tan \left ( dx+c \right ) \right ) ^{3/2}}}-1/10\,{\frac{{a}^{2}}{ \left ( a+ia\tan \left ( dx+c \right ) \right ) ^{5/2}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.29604, size = 845, normalized size = 6.35 \begin{align*} \frac{{\left (15 \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{1}{a^{5} d^{2}}} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left ({\left (2 \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{1}{a^{5} d^{2}}} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt{2} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}{\left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-i \, d x - i \, c\right )}\right ) - 15 \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{1}{a^{5} d^{2}}} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (-{\left (2 \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{1}{a^{5} d^{2}}} e^{\left (2 i \, d x + 2 i \, c\right )} - \sqrt{2} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}{\left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-i \, d x - i \, c\right )}\right ) + \sqrt{2} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}{\left (83 \, e^{\left (6 i \, d x + 6 i \, c\right )} + 64 \, e^{\left (4 i \, d x + 4 i \, c\right )} - 16 \, e^{\left (2 i \, d x + 2 i \, c\right )} + 3\right )} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-6 i \, d x - 6 i \, c\right )}}{120 \, a^{3} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan ^{3}{\left (c + d x \right )}}{\left (a \left (i \tan{\left (c + d x \right )} + 1\right )\right )^{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan \left (d x + c\right )^{3}}{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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